From ( \fracm v^2r = \fracG M_T mr^2 ) ⇒ ( v = \sqrt\fracG M_Tr ). [ v = \sqrt\frac(6.67 \times 10^-11)(5.98 \times 10^24)6.97 \times 10^6 \approx \sqrt5.72 \times 10^7 \approx 7.56 \times 10^3 , \textm/s ]
[ g = \fracG M_Tr^2 = \frac(6.67 \times 10^-11)(5.98 \times 10^24)(6.97 \times 10^6)^2 ] [ g \approx 8.20 , \textN/kg \quad (\textapprox. 83.6% of surface gravity) ] solucionario fisica 2 bachillerato santillana
Buy a used teacher’s edition from a second-hand academic bookstore or ask your school’s department head for a digital access code. From ( \fracm v^2r = \fracG M_T mr^2