Average increase per decade = [(55-45)+(68-55)+(84-68)] / 3 = (10+13+16)/3 = 13,000 per decade P2030 = P2010 + 2 × 13,000 = 84,000 + 26,000 = 110,000
Using h_f = K × Q^1.852 with K = 10.67×L / (C^1.852×D^4.87) D=0.25m → D^4.87 = 0.25^4.87 = 0.25^4 × 0.25^0.87 = 0.003906 × 0.305 = 0.001191 C^1.852 = 100^1.852 = 5120 (approx) water supply engineering solved problems pdf
Make a mass diagram (cumulative supply – cumulative demand): Average increase per decade = [(55-45)+(68-55)+(84-68)] / 3